Math Community

[cptheslayer 2]

I will help those that needs help with Math. I will also try to make Math lessons as time allows me to do it.

[BloodyMary 0]

yay.

[the necromancer 2]

mm my math teacher at skool wants me 2 tute yr 7 n00bs

but im too busy

[Speedy 11]

aha

[{{clan}}CocKTail- 0]

aha

are u drunken?

if no can u teach me physik? lol

[IndominusRex 13]

Wow CP!

Are you sure you can help me with AP Calculus BC? You sure not forget it already?

And you know what, last night, I did not sleep because I have to finish my AP US History decade project

[cptheslayer 2]

I am in my Math 310 class now. I have just given my project presentation. If you have Mathematica, I will send you a copy.

What is AP Caculus BC? I mean what math topics does it cover? Is it derivatives, integrations, boundaries, limits, or what?

[Sinophile 41]

Hey cptheslayer, I got some grade 11 maths. You probably be able to do it: Functions and relations

Ill just copy the quesiton right from the book:

What is the range of the following function, assuming the domain in each case is all the real numbers which give meaning?

y = (1/2)^x

goddammit

[[LOT]rundown 3]

Isn't the end of the range infinite? Don't know about the beginning though (?,infinite)

Cp will know.

[[LOT]Eclipse 0]

i pwn at math. u pppl might be able to beat me in br but not math. uber ownage

[[LOT]rundown 3]

Lol so what's the answer

[[LOT]Eclipse 0]

i cant read it its the problem with computer million lines through screen

[[LOT]rundown 3]

O, I'm sorry.

[cptheslayer 2]

let me try. long time no working with finding range or domain. but i think i still remember how.

y=(1/2)^x where x is any real number.

when x=0, y=1

when x is in (0, infinity), y is in (0, 1).

when x is in (-infinity,0), we can look at y=2^x where x in (0, infinity) instead of y=(1/2)^x. So y is in the interval (1, infinity).

Therefore, the range is (0, infinity) for x in (-infinity, infinity).

Check me on this.

[[LOT]Eclipse 0]

mein kampf i with i could see the problem in 2 days i will be able to .

[{{clan}}MeD 1]

let me try. long time no working with finding range or domain. but i think i still remember how.

y=(1/2)^x where x is any real number.

when x=0, y=1

when x is in (0, infinity), y is in (0, 1).

when x is in (-infinity,0), we can look at y=2^x where x in (0, infinity) instead of y=(1/2)^x. So y is in the interval (1, infinity).

Therefore, the range is (0, infinity) for x in (-infinity, infinity).

Check me on this.

It's right.

I would say : [For x--> - infinity]

limit 1^x = 1

x ---> - infinity

limit 2^x = 0+

x ---> - infinity

Therefore limit (1/2)^x = 1/0+ = + infinity.

.................x --> - infinity

[For x--> + infinity]

limit 1^x = 1

x--> + infinity

limit 2^x = + infinity

x --> + infinity

Therefore limit (1/2)^x = 1/+ infinity = 0.

...............x---> + infinity

So the range of x when x is in (- infinity, + infinity) is (0, + infinity).

This is how in France, we would write it but i had some problems to write it correctly. It is easier and more clear on a paper lol.

[cptheslayer 2]

yes, that is right. i wish i could use math symbols here. but we can't.

Med, nice job.

Now, what is the integration of 1/x with respect to x?

[{{clan}}MeD 1]

Hehe thanks but integration, logarithms, exponential functions etc... are things I don't know yet. I will see all these little things next year.

However i can tell you other things like geometry in space, vectors, mecanic forces, weightlessness, chimic reactions....etc (in fact, physic and chemistry.)

[cptheslayer 2]

i dont know chemistry. a bit about physics.

[reNekRoManT 3]

u dont know physik?

heheh then u hehheh i cant says

[Grayback 14 9]

I like Math.